0=n^2-2n-168

Solution for 0=n^2-2n-168 equation:

0=n^2-2n-168

We move all terms to the left:

0-(n^2-2n-168)=0

We add all the numbers together, and all the variables

-(n^2-2n-168)=0

We get rid of parentheses

-n^2+2n+168=0

We add all the numbers together, and all the variables

-1n^2+2n+168=0

a = -1; b = 2; c = +168;
Δ = b2-4ac
Δ = 22-4·(-1)·168
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-26}{2*-1}=\frac{-28}{-2}
=+14
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+26}{2*-1}=\frac{24}{-2}
=-12
$